If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2+28x-150=0
a = 8; b = 28; c = -150;
Δ = b2-4ac
Δ = 282-4·8·(-150)
Δ = 5584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5584}=\sqrt{16*349}=\sqrt{16}*\sqrt{349}=4\sqrt{349}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{349}}{2*8}=\frac{-28-4\sqrt{349}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{349}}{2*8}=\frac{-28+4\sqrt{349}}{16} $
| 1=1•4(2x+8) | | 8b-10=-26 | | -k+10=27 | | -6a+10=112 | | -4(7n+1)+5(n-7)=53 | | 5x+7=260 | | 75+x+122=180 | | 21d=0.d | | -9-15y=18y+9(-6y+20) | | 3-8r=3 | | (x−3)−2=6−2(x+1) | | 10p-20+2p=-2(-p-3)+8p | | 2x+x^2=0.25 | | 7(4+4r)=5(5r+2) | | -7+8a=121 | | 2x-6×+4=0 | | 2=(5x-8) | | -(j-33)=-15 | | -17v=-9-5(5v-13) | | t/7+57=61 | | 5m-6=3m-2 | | 5k=4(2k+14)-11 | | 2-1/5x-23=73/10x+34 | | 3(4w-5)=2(6w+1)-7 | | 9c+19=100 | | -2(2u-20)+19=3u-20-19 | | 2(5y)=20 | | −18=−9n | | B=1/4f×2 | | 20t=-2(-8t-17)+5t | | -9(t-2)=4(t+9) | | 15n+9-2n=-17n+9(4n+13) |